咨詢內(nèi)容:
您好,
通達(dá)信里面的一段代碼,其中涉及到SMA函數(shù),見最后一句,請教一下,如何把SMA轉(zhuǎn)換成,金字塔圖表逐K模式能夠識別的代碼呢?
非常感謝!
JJ:=(HIGH+LOW+CLOSE)/3;
QJ0:=VOL/IF(HIGH=LOW,4,HIGH-LOW);
QJ1:=IF(0,QJ0*(JJ-MIN(CLOSE,OPEN)),QJ0*IF(HIGH=LOW,1,(MIN(OPEN,CLOSE)-LOW)));
QJ2:=IF(0,QJ0*(MIN(OPEN,CLOSE)-LOW),QJ0*IF(HIGH=LOW,1,(JJ-MIN(CLOSE,OPEN))));
QJ3:=IF(0,QJ0*(HIGH-MAX(OPEN,CLOSE)),QJ0*IF(HIGH=LOW,1,(HIGH-MAX(OPEN,CLOSE))));
QJ4:=IF(0,QJ0*(MAX(CLOSE,OPEN)-JJ),QJ0*IF(HIGH=LOW,1,(MAX(CLOSE,OPEN)-JJ)));
DDX:=((QJ1+QJ2)-(QJ3+QJ4))/IF(0,10000,10000),COLOR00AAAA,LINETHICK;
V2:=SMA(IF(C>=REF(C,1),DDX,-DDX/100),2,1);//幫忙轉(zhuǎn)換成金字逐K模式下能夠識別的代碼
?
?來源: www.tumamayizhan.com
金字塔資深技術(shù):
這段直接就可以用的